为什么放到win下编译就会成功，而放在xcode上就说我模凌两可？难道不可以重新定义它的bitset？

#ifndef bitset_h
#define bitset_h
template<int N>
class bitset {
private:
bool bit[N];
public:
bitset() {
for (int i = 0; i < N; i++)
bit[i] = false;
}
void set(int pos) {
if (pos >= 0 && pos < N) {
bit[pos] = true;
}
}
int count() {
int sum = 0;
for (int i = 0; i < N; i++) {
if (bit[i] == 1)
sum++;
}
return sum;
}
bool test(int pos) {
if (pos >= 0 && pos < N) {
return (bit[pos] == 1);
}
return false;
}
bool any() {
return count();
}
bool none() {
return count() == 0;
}
bool all() {
return count() == N;
}
void reset(int pos) {
if (pos >= 0 && pos < N) {
bit[pos] = false;
}
}
friend std::ostream& operator<<(std::ostream& outP, const bitset& _bit) {
for (int i = N - 1; i >= 0; i--) {
outP << _bit.bit[i];
}
return outP;
}
bitset<N> operator~() {
bitset<N> out;
for (int i = 0; i < N; i++) {
out.bit[i] = bit[i] == false;
}
return out;
}
bool operator==(const bitset<N> & othbit) const {
for (int i = 0; i < N; i++) {
if (bit[i] != othbit.bit[i]) {
return false;
}
}
return true;
}
bool operator!=(const bitset<N> & othbit) const {
int sum = 0;
for (int i = 0; i < N; i++) {
if (bit[i] == othbit.bit[i]) {
sum++;
}
}
return !(sum == N);
}
bitset<N>& operator=(const bitset<N> & othbit) {
for (int i = 0; i < N; i++) {
bit[i] = othbit.bit[i];
}
return *this;
}
bitset<N> operator&(const bitset<N> & othbit) const {
bitset<N> out;
for (int i = 0; i < N; i++) {
out.bit[i] = bit[i] & othbit.bit[i];
}
return out;
}
bitset<N>& operator&=(const bitset<N> & othbit) {
*this = *this & othbit;
return *this;
}
bitset<N> operator|(const bitset<N> & othbit) const {
bitset<N> out;
for (int i = 0; i < N; i++) {
out.bit[i] = bit[i] | othbit.bit[i];
}
return out;
}
bitset<N>& operator|=(const bitset<N> & othbit) {
*this = *this | othbit;
return *this;
}
bitset<N> operator^(const bitset<N> & othbit) const {
bitset<N> out;
for (int i = 0; i < N; i++) {
out.bit[i] = bit[i] ^ othbit.bit[i];
}
return out;
}
bitset<N>& operator^=(const bitset<N> & othbit) {
*this = *this ^ othbit;
return *this;
}
bitset<N> operator<<(int pos) const {
bitset<N> out;
for (int i = 0; i < pos; i++) {
out.bit[i] = false;
}
for (int i = pos; i < N; i++) {
out.bit[i] = bit[i - pos];
}
return out;
}
bitset<N>& operator <<= (int pos) {
*this = *this << pos;
return *this;
}
bitset<N> operator>>(int pos) const {
bitset<N> out;
for (int i = N - 1; i >= N - pos - 1; i--) {
out.bit[i] = true;
}
for (int i = 0; i < N - pos - 1; i++) {
out.bit[i] = bit[i + pos];
}
return out;
}
bitset<N>& operator >>= (int pos) {
*this = *this >> pos;
return *this;
}
bool operator[](int pos) {
return (bit[pos]);
}
};
#endif /* bitset_h */

额，百度恶心的排版，又不能用markdown