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仅看楼主
level 11
丨不死神话丨 楼主
sinα+cosα=tanα 则α=？
2011年02月13日 16点02分 1
level 11
丨不死神话丨 楼主
sinα+cosα=tanα 则α=？
2011年02月13日 16点02分 2
level 9
AromaRhyme
全部换成tan α/2……计算出这个的数值
2011年02月13日 16点02分 3
level 14
Monkey_飞
AR一出，数学灰飞烟灭…………
2011年02月13日 17点02分 4
level 8
147gta
初步认为无解。。。
2011年02月13日 17点02分 5
level 11
アーレス
有
2011年02月13日 17点02分 6
level 11
丨不死神话丨 楼主
四次方程
2011年02月14日 03点02分 8
level 10
残皿轻梦
{{x -> -ArcCos[
      1/2 (1/2 + 1/
         Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] -
         1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] - (
         3^(2/3) Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(
         2 (2 (9 + Sqrt[129]))^(1/3)) + ((3 (9 + Sqrt[129]))^(1/3)
           Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(4 2^(2/3)) -
         1/8 ((2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3))^(3/2) -
         1/2 \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) + (3^(
            2/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
               2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
               Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
                2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]))/(2 (2 (9 +
                Sqrt[129]))^(1/3)) - 1/(
         4 2^(2/3))(3 (9 + Sqrt[129]))^(
          1/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) -
         1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(

2011年02月14日 03点02分 9
level 10
残皿轻梦
           1/3)] \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) -
         1/8 (-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])^(
          3/2))]}, {x -> -ArcCos[
      1/2 (1/2 + 1/
         Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] -
         1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] - (
         3^(2/3) Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(
         2 (2 (9 + Sqrt[129]))^(1/3)) + ((3 (9 + Sqrt[129]))^(1/3)
           Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(4 2^(2/3)) -
         1/8 ((2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3))^(3/2) +
         1/2 \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) - (3^(
            2/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
               2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
               Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
                2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]))/(2 (2 (9 +

2011年02月14日 03点02分 10
level 10
残皿轻梦
                Sqrt[129]))^(1/3)) + 1/(
         4 2^(2/3))(3 (9 + Sqrt[129]))^(
          1/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) +
         1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(
          
           1/3)] \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
             Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
              2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) +
         1/8 (-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) - 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])^(3/2))]}, {x ->
    ArcCos[1/
      2 (1/2 - 1/
        Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
         2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] +
        1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] + (
        3^(2/3) Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(
        2 (2 (9 + Sqrt[129]))^(1/3)) - ((3 (9 + Sqrt[129]))^(1/3)
          Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(4 2^(2/3)) +
        1/8 ((2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3))^(3/2) -
        1/2 \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (

2011年02月14日 03点02分 11
level 10
残皿轻梦
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) + (
        3^(2/3) Sqrt[-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
          Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]])/(
        2 (2 (9 + Sqrt[129]))^(1/3)) - 1/(
        4 2^(2/3))(3 (9 + Sqrt[129]))^(
         1/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) +
        1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(
          1/3)] \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) -
        1/8 (-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
           Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])^(3/2))]}, {x ->
    ArcCos[1/
      2 (1/2 - 1/
        Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
         2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] +
        1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)] + (
        3^(2/3) Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(
        2 (2 (9 + Sqrt[129]))^(1/3)) - ((3 (9 + Sqrt[129]))^(1/3)

2011年02月14日 03点02分 12
level 10
残皿轻梦
          Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])/(4 2^(2/3)) +
        1/8 ((2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3))^(3/2) +
        1/2 \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) - (
        3^(2/3) Sqrt[-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
          Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]])/(
        2 (2 (9 + Sqrt[129]))^(1/3)) + 1/(
        4 2^(2/3))(3 (9 + Sqrt[129]))^(
         1/3) \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) -
        1/2 Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
          2 2^(2/3))/(3 (9 + Sqrt[129]))^(
          1/3)] \[Sqrt](-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
            Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
             2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)]) +
        1/8 (-(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) + (
           2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3) + 4/
           Sqrt[(2 (9 + Sqrt[129]))^(1/3)/3^(2/3) - (
            2 2^(2/3))/(3 (9 + Sqrt[129]))^(1/3)])^(3/2))]}}
2011年02月14日 03点02分 13
level 10
残皿轻梦
直接复制的，还没验算。
2011年02月14日 03点02分 14
level 6
啥话我都说
表 示 我 感 觉 心 死 不 会 活 了
2011年02月14日 03点02分 15
level 11
アーレス
知道中国教育为什么落后了么，因为学生往往会纠结于这种其实很简单的东西而浪费大量时间。美国学生如果想求解的话，只需拿起手边的TI计算器，几秒钟就能得出答案。
2011年02月14日 03点02分 16
level 14
Monkey_飞
我卡…………吐了………………………………………………………………
话说打这些东西得用多长时间……
2011年02月14日 04点02分 17
level 1
两尛猜猜
-15.表示从来没活过…
2011年02月14日 04点02分 18
level 10
残皿轻梦
{{x -> -1.0383103507 -
     0.7575305696 \[ImaginaryI]}, {x -> -1.0383103507 +
     0.7575305696 \[ImaginaryI]}, {x -> 2.698449008}, {x ->
    0.9489680204}}
还是这个看着方便点。
2011年02月14日 04点02分 19
level 10
残皿轻梦
回复：17楼
把方程敲进mathematica跑出结果一复制就完了……
2011年02月14日 04点02分 20
level 14
Monkey_飞
回复：20楼
原来是计算机求解…………[汗]
我说谁能这么强大打出这么多东西…………
mathematica，三大数学软件之一啊…………………………
2011年02月14日 04点02分 21
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