解析见答案#include int main(){ int a[lbk]5[rbk][lbk]5[rbk] = {0,1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16,17,18,19,20,21,22,23,24}; int i,j,sum = 0; printf("5*5矩阵为:\n"); for (i = 0; i < 5; i++) { for (j = 0; j < 5; j++) printf("%4d",a[lbk]i[rbk][lbk]j[rbk]); printf("\n"); } for(i =0;i < 5; i++) sum += a[lbk]i[rbk][lbk]i[rbk]; printf("\n"); printf(" sum=%4d\n",sum); return 0;}