就比如{"_id":"160c88652d47d0be60bfbfed25111412","type":"福韵行业分类","parent":"a9b7ba70783b617e9998dc4dd82eb3c5","parentName":"轻工制造","dCName":"木材加工和木、竹、藤、棕、草制品业","dEName":"阿萨德","dVal":"1190","level":2,"index":19}
我想把里面的parent和parentName合并变成{"_id":"160c88652d47d0be60bfbfed25111412","type":"福韵行业分类","parent":"a9b7ba70783b617e9998dc4dd82eb3c5","parentName":"轻工制造","dCName":"木材加工和木、竹、藤、棕、草制品业","dEName":"阿萨德","dVal":"1190","level":2,"index":19,"demo":"parent+parentName"}

filter

for..in获取键名然后拼接，或者object.keys()获取键名

对象名.demo=对象名.parent+parentName就行了，你这是如果是json数据，还得转成js里的对象然后再点语法直接操作起来就行了