\[Omega] = 2*Pi*433*10^6;
\[Mu]1 = 4*Pi*10^-7; \[Mu]2 = 4*Pi*10^-7; \[Epsilon]1 =
56.873*8.854*10^-12; \[Epsilon]2 =
8.854*10^-12; \[Sigma]1 = 0.80484; \[Sigma]2 = 0;
a = 0.15; Pz = 1;
\[Rho]1 = 0.09; \[Phi]1 = 0; z1 = 0; \[Rho] = 0.15; \[Phi] = 0; z = 0;
k1 = Sqrt[(\[Omega]^2*\[Mu]1*\[Epsilon]1 +
I*\[Omega]*\[Mu]1*\[Sigma]1)];
k2 = Sqrt[(\[Omega]^2*\[Mu]2*\[Epsilon]2 +
I*\[Omega]*\[Mu]2*\[Sigma]2)];
k1\[Rho] = Sqrt[k1^2 - kz^2];
k2\[Rho] = Sqrt[k2^2 - kz^2];
H2 = -HankelH1[m + 1, k2\[Rho]*a] +
m/(k2\[Rho]*a)*HankelH1[m, k2\[Rho]*a];
H2\[Rho] = -HankelH1[m + 1, k2\[Rho]*\[Rho]] +
m/(k2\[Rho]*\[Rho])*HankelH1[m, k2\[Rho]*\[Rho]];
H1 = -HankelH1[m + 1, k1\[Rho]*a] +
m/(k1\[Rho]*a)*HankelH1[m, k1\[Rho]*a];
H1\[Rho] = -HankelH1[m + 1, k1\[Rho]*\[Rho]] +
m/(k1\[Rho]*\[Rho])*HankelH1[m, k1\[Rho]*\[Rho]];
J1 = -BesselJ[m + 1, k1\[Rho]*a] +
m/(k1\[Rho]*a)*BesselJ[m, k1\[Rho]*a];
J1\[Rho] = -BesselJ[m + 1, k1\[Rho]*\[Rho]] +
m/(k1\[Rho]*\[Rho])*BesselJ[m, k1\[Rho]*\[Rho]];
c1 = kz*m*HankelH1[m, k2\[Rho]*a]*
BesselJ[m, k1\[Rho]*a]*(1/k2\[Rho]^2 - 1/k1\[Rho]^2);
c2 = (I*\[Omega]*\[Mu]2*a)/k2\[Rho]*H2*BesselJ[m, k1\[Rho]*a] - (
I*\[Omega]*\[Mu]1*a)/k1\[Rho]*HankelH1[m, k2\[Rho]*a]*J1;
c3 = (k2^2*a)/(I*\[Omega]*\[Mu]2*k2\[Rho])*H2*
BesselJ[m, k1\[Rho]*a] - (k1^2*a)/(I*\[Omega]*\[Mu]1*k1\[Rho])*
HankelH1[m, k2\[Rho]*a]*J1;
q1 = kz*m*HankelH1[m, k1\[Rho]*a]*
HankelH1[m, k2\[Rho]*a]*(1/k1\[Rho]^2 - 1/k2\[Rho]^2);
q2 = (I*\[Omega]*\[Mu]1*a)/k1\[Rho]*H1*HankelH1[m, k2\[Rho]*a] - (
I*\[Omega]*\[Mu]2*a)/k2\[Rho]*HankelH1[m, k1\[Rho]*a]*H2;
q3 = (k1^2*a)/(I*\[Omega]*\[Mu]1*k1\[Rho])*H1*
HankelH1[m, k2\[Rho]*a] - (k2^2*a)/(I*\[Omega]*\[Mu]2*k2\[Rho])*
HankelH1[m, k1\[Rho]*a]*H2;
r11 = (c1*q1 - c2*q3)/(c1^2 - c2*c3);
r12 = (c1*q2 - c2*q1)/(c1^2 - c2*c3);
r21 = (c1*q3 - c3*q1)/(c1^2 - c2*c3);
r22 = (c1*q1 - c3*q2)/(c1^2 - c2*c3);
mRange = Range[40, 40, 1];
h2z = -((\[Omega]*\[Mu]1*Pz)/(8 \[Pi]*k1^2))*
Sum[E^(I*m*(\[Phi] - \[Phi]1))*
NIntegrate[
E^(I*kz*(z - z1))*BesselJ[m, k1\[Rho]*\[Rho]1]*k1\[Rho]^2*r21*
BesselJ[m, k1\[Rho]*a]*HankelH1[m, k2\[Rho]*\[Rho]]/
HankelH1[m, k2\[Rho]*a], {kz, 0, 500},
Exclusions -> {HankelH1[m, k2\[Rho]*a] == 0, kz^2 == k1^2,
kz^2 == k2^2}, PrecisionGoal -> 5, WorkingPrecision -> 10,
MaxRecursion -> 100], {m, -#, #}] & /@ mRange
moUez = Abs[h2z]

嗯？又到了折腾强振荡嵌套积分的季节了？我想说的还是这几句：https://zhidao.baidu.com/question/591280726916368885.html
这类问题本来就难，不了解问题背景，更是几乎给不出建议。