level 5
念奴娇929
楼主
这是我的计算过程,我想给图片里的 方程加的边界条件是当x^2+y^2=0.03时,D1=1,因为自变量是x,y,z,请问这种边界条件怎么加呢?先蟹蟹大家啦
eqn6 = (-8.30996*10^6 - 1/(x^2 + y^2)) D1[x, y,
z] + (0. + 2.371*10^7 I)
\!\(\*SuperscriptBox[\(D1\),
TagBox[
RowBox[{"(",
RowBox[{"0", ",", "0", ",", "1"}], ")"}],
Derivative],
MultilineFunction->None]\)[x, y, z]
DSolve[eqn6 == 0, D1[x, y, z], {x, y, z}]

2020年05月09日 06点05分
1
eqn6 = (-8.30996*10^6 - 1/(x^2 + y^2)) D1[x, y,
z] + (0. + 2.371*10^7 I)
\!\(\*SuperscriptBox[\(D1\),
TagBox[
RowBox[{"(",
RowBox[{"0", ",", "0", ",", "1"}], ")"}],
Derivative],
MultilineFunction->None]\)[x, y, z]
DSolve[eqn6 == 0, D1[x, y, z], {x, y, z}]

