level 1
qdcvhjm
楼主
a = 9.6
b = 0.28
epsln = 20
epsl = 1
c = 3
fmhz = 900000000
R = 5
h = 200
u = 1
Dm = 2
T = 5
\[Lambda] = 1
l[r_] := ((epsln*4*\[Pi]*fmhz/c)*(1 -
1/(1 + a*
E^(a*b - b*ArcTan[(h/r)]*180/\[Pi]))) + (epsl*4*\[Pi]*
fmhz/c)*(1/(1 +
a*E^(a*b - b*ArcTan[(h/r)]*180/\[Pi]))))^(-1)*((r^2 +
h^2)^(-1))
p[rr_] := (1/(1 + (T *l[rr])/l[rm])) (1/(1 + (T *l[rr + v])/l[rm + v]))
f[rrr_] := If[0 < rrr < R, 1/(\[Pi] *rrr^2), 0]
s[v_] := 2/Dm^2 \!\(
\*SubsuperscriptBox[\(\[Integral]\), \(0\), \(Dm\)]\(
\*SuperscriptBox[\(E\), \(\((\(-\[Lambda]\))\)*2\ \[Pi] \(
\*SubsuperscriptBox[\(\[Integral]\), \(-10000\), \(10000\)]\((1 -
\*SuperscriptBox[\(E\), \(\(-c\)*\((1 -
\*SubsuperscriptBox[\(\[Integral]\), \(-10000\), \(10000\)]2*\[Pi]*\
p[x + y]\ \ *f[y]*y \[DifferentialD]y)\)\)])\)*
x \[DifferentialD]x\)\)] rm \[DifferentialD]rm\)\)
Plot[s[v], {v, 0, 20}]

2019年04月23日 12点04分
1
b = 0.28
epsln = 20
epsl = 1
c = 3
fmhz = 900000000
R = 5
h = 200
u = 1
Dm = 2
T = 5
\[Lambda] = 1
l[r_] := ((epsln*4*\[Pi]*fmhz/c)*(1 -
1/(1 + a*
E^(a*b - b*ArcTan[(h/r)]*180/\[Pi]))) + (epsl*4*\[Pi]*
fmhz/c)*(1/(1 +
a*E^(a*b - b*ArcTan[(h/r)]*180/\[Pi]))))^(-1)*((r^2 +
h^2)^(-1))
p[rr_] := (1/(1 + (T *l[rr])/l[rm])) (1/(1 + (T *l[rr + v])/l[rm + v]))
f[rrr_] := If[0 < rrr < R, 1/(\[Pi] *rrr^2), 0]
s[v_] := 2/Dm^2 \!\(
\*SubsuperscriptBox[\(\[Integral]\), \(0\), \(Dm\)]\(
\*SuperscriptBox[\(E\), \(\((\(-\[Lambda]\))\)*2\ \[Pi] \(
\*SubsuperscriptBox[\(\[Integral]\), \(-10000\), \(10000\)]\((1 -
\*SuperscriptBox[\(E\), \(\(-c\)*\((1 -
\*SubsuperscriptBox[\(\[Integral]\), \(-10000\), \(10000\)]2*\[Pi]*\
p[x + y]\ \ *f[y]*y \[DifferentialD]y)\)\)])\)*
x \[DifferentialD]x\)\)] rm \[DifferentialD]rm\)\)
Plot[s[v], {v, 0, 20}]
