log.out.20160919.0028.log:[20160919094133005820][ Run][2016-09-19 09:41:34.073] httpClient doPost:[respMsg:<?xml ><soapenv:Envelope xmlns:soapenv="><menuid>0</menuid><process_code>ccqrycustinfo</process_code><verify_code>0</verify_code><resp_tim
请问用awk怎么能打印出这三段
log.out.20160919.0028.log 20160919094133005820 ccqrycustinfo

自顶

有大神在吗

用gensub（）来处理就可以了。
a = gensub(...)
b = gensub(...)
c = gensub(...)
print a, b, c