解三元一次方程：a*x+y=2，y+z=b，x-z=c,x,y,z是变量，a,b,c是常量我的命令 solve({a*x+y=2，y+z=b，x-z=c,})；可系统总以为a,b,c也是变量；我该如何做？ 高手赐教

solve({x+y = 5, x-z = 1, y+z = 94}, [x, y, z])Maple不太好用。在Mathematica里用RowReduce处理方程矩阵。方程的矩阵[{{a, 1, 0, 2}, {0, 1, 1, b}, {1, 0, -1, c}}] ->{{1, 0, 0, (2 - b - c)/(-1 + a)}, {0, 1, 0, (-2 + a b + a c)/(-1 + a)}, {0, 0, 1, (2 - b - a c)/(-1 + a)}}结果就出来了：x=(2 - b - c)/(-1 + a)y=(-2 + a b + a c)/(-1 + a)z=(2 - b - a c)/(-1 + a)

在Maple里输入：>with(linalg)>rref(Matrix(3,4,[a, 1, 0, 2,0, 1, 1, b,1, 0, -1, c]))得到Matix[[1,0,0,-(-2+b+c)/(a-1)],[0,1,0,(b a+c a-2)/(a-1)],[0,0,1,-(c a-2+b)/(a-1)]]同样用矩阵法解出方程

好久没来了 问题已解决 居然有人回帖 不容易啊 楼上的太繁琐u := a*x+y = 2;v := y+z = b;w := x-z = c;solve({v, u, w}, {z, x, y});很简单的