请大神给一个克隆冲突的js。

话说这一关我已经试了几十次但还是过不去哦

已过，哈哈哈

说下策略吧，因为装备不差了

说下策略吧，因为装备不差了

1.使用旗子使英雄移动到蓝方弓箭手旁，确保先杀一部分弓箭手；
2.当血量不足时快速移动到安全地带。

python的策略，你可以对应的转化成js的。
基本策略，先上去杀掉最弱的一部分敌人，也就是杀掉敌人的一堆小兵。然后用旗帜引导英雄躲到你的弓箭手后面。。这时候敌人会追着你跑。相当于把对方英雄引入到你的埋伏圈了。
======================================
def findWeakEnemy(weak):
weak = None
weakHealth = 99999
enemyID = 0
enemies = hero.findEnemies()
while enemyID < len(enemies):
enemy = enemies[enemyID]
if enemy.health < weakHealth:
weak = enemy
weakHealth = enemy.health
enemyID += 1
return weak
while True:
#hero.wait(3)
enemies = hero.findEnemies()
enemyID = 0
enemy = enemies[enemyID]
small = findWeakEnemy(enemy)
flag = hero.findFlag("green")
if small and hero.distanceTo(small) < 30:
while small.health > 0:
if flag:
hero.pickUpFlag(flag)
elif hero.isReady("cleave"):
#hero.moveXY(small.pos.x, small.pos.y)
hero.cleave(small)
elif hero.isReady("bash"):
hero.bash(small)
else:
hero.attack(small)

js的代码也有~~
// 你需要更好的策略和好的装备来赢得这关。
NO.1战士
loop {
var weakestenemy = null ;
var leasthealth = 999999 ;
var enemys = this.findEnemies();
var enemyindex = 0 ;
while (enemyindex < enemys.length) {
var enemy = enemys[enemyindex] ;
var health = enemy.health;
if (health < leasthealth) {
leasthealth = health ;
weakestenemy = enemy ;
}
enemyindex ++ ;
}
if (weakestenemy && this.distanceTo(weakestenemy) < 40) {
while (weakestenemy.health > 0) {
if (this.isReady("cleave")) {
this.cleave(weakestenemy);
}
else if (this.isReady("bash")){
this.bash(weakestenemy);
}
else {
this.attack(weakestenemy);
}
}
}
}
NO.2法师
// 你需要更好的策略和好的装备来赢得这关。
loop {
var flag = this.findFlag();
if (flag) {
this.pickUpFlag(flag);
}
var weakf = null;
var heal = 99999 ;
var frindex = 0 ;
var friends = this.findFriends();
while (frindex < friends.length) {
var friend = friends[frindex] ;
var health = friend.health ;
if (health < heal) {
weakf = friend ;
heal = health;
}
frindex ++ ;
}
var weakenemy = null ;
var heals = 99999 ;
var enemyindex = 0 ;
var enemys = this.findEnemies();
while (enemyindex < enemys.length) {
var enemy = enemys[enemyindex] ;
var healths = enemy.health ;
if (healths < heals) {
weakenemy = enemy ;
heals = healths ;
}
enemyindex ++ ;
}
if (this.canCast("summon-fangrider")) {
this.cast("summon-fangrider");
}
if (weakf) {
if (this.canCast("regen")) {
this.cast("regen", weakf);
}
else {
if (this.distanceTo(weakenemy) < 40) {
this.attack(weakenemy);
}
}
}
}

沙漠的 一打宝石 这关怎么过啊？给个答案。

JavaScript代码，过很简单，看你操作了，主要是先杀弓箭手，然后躲到你的弓箭手后面就好
while(true) {
var flagB = hero.findFlag("black");
var flagG = hero.findFlag("green");
var enemy = hero.findNearestEnemy();
if (flagB && hero.isReady("cleave")) {
hero.pickUpFlag(flagB);
hero.cleave(enemy);
} else if (flagG) {
hero.pickUpFlag(flagG);
} else if (enemy && enemy.type != "sand yak") {
hero.attack(enemy);
}
}

首先，选一个血多的武士，我选的是 Ida Justheart女爵。然后尽量穿血多一点的盔甲，拿个好盾，拿把入门级的刀。经过多次试验，最终通关代码如下：
var enemies = hero.findEnemies();
var enemyIndex = 0;
while (enemyIndex < enemies.length) {
var enemy = enemies[enemyIndex];
if (enemy.type == 'archer') {
while (enemy.health > 0) {
hero.attack(enemy);
}
}
enemyIndex++;
}
hero.moveXY(62, 70);
while (true) {
if (hero.isReady("bash")) {
hero.bash(hero.findNearestEnemy());
} else {
hero.shield();
}
}

需要选多血的吗

ha

索引值：用来选择序列中元素的值。

元素：序列中的一个值