thinkphp大神帮忙看看，网站首页广告图片，切换图片时置顶左边，代码写错了么?
<div id="banner">
<div id="slider-wrapper">
<div id="slider" class="nivoSlider">
<?php foreach($bannerlists as $row){ ?>
<a href="<?php echo $row['p_url']; ?>" target="_blank"><img src="<?php echo $row['p_img']; ?>" alt="<?php echo $row['p_title']; ?>" width="1280" height="520" /></a>
<?php } ?>
</div>
</div>
</div>
前端网页显示源码：
<div id="banner">
<div id="slider-wrapper">
<div id="slider" class="nivoSlider">
<a href="/index.php/goods.html?id=27" target="_blank"><img src="/data/image/20150420/20
15042015325
8_46403.jpg" width="1280" height="520" /></a> <a href="/index.php/goods.html?id=74" target="_blank"><img src="/data/image/20150916/20
15091613452
0_19126.jpg" width="1280" height="520" /></a> <a href="/index.php/category.html?letter=cpzx" target="_blank"><img src="/data/image/20150420/20
15042015322
8_38957.jpg" width="1280" height="520" /></a> <a href="/index.php/goods.html?id=578" target="_blank"><img src="/data/image/20150916/20
15091613514
3_11667.jpg" width="1280" height="520" /></a> <a href="/index.php/goods.html?id=570" target="_blank"><img src="/data/image/20150916/20
15091613494
1_51261.jpg" width="1280" height="520" /></a> </div>

顶，楼下好人帮帮楼主

如图，置顶左边，最右边空白，中间靠右的是第二张图片，求大神解惑

代码截图，你直接复制不想看