public function BfContypeinfoSel($contypeId) {
$contypename = M ( 'Contype' );
$contypeId=$_POST('Code');
$contypenamelist = $contypename->where ( 'Code like \'%'.$contypeId.'%\'' )->field ( 'Code,ChName,EnName,Remark' )->find ();
$this->ajaxReturn ( $contypenamelist, 'json' );
}
这个查询的方法有什么问题吗 为啥我在前台调用的时候总是说我未定义contypeId