原题：Plot a Lisajous curve where x = cos(15t) and y = sin(13t).
Try to do this first stepping t from 0 to 2*PI stepping 0.1 (too coarse) and then try finer gradations.
Look at the example of plotting a function if you have any questions about how to use translate and scale to set up your code.
翻译：绘制一个李萨如曲线 x=cos(15t) y=sin(13t).
尝试 第一步 改变t从0到2π 步进0.1（太粗糙） 然后尝试修改完美它。

@子衿Woody

抱歉看到的晚了，程序如下，比较简单的参数曲线绘制程序：
float t = 0;
float dt = 0.1;
float s = 100; // size
void setup() {
size(500,500);
stroke(255);
}
void draw() {
background(0);
translate(250,250);
t = 0;
for(t=dt; t<2*PI; t+=dt){
line(s*cos(15*t), s*sin(13*t), s*cos(15*(t-dt)), s*sin(13*(t-dt)));
}
}

以后有问题的话尽量早点发布求助帖，不然不一定能及时看见