level 2
笨笨的code
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<SCRIPT LANGUAGE="JavaScript">
var zTreeObj; var setting = {
async: {
enable: true,
url:"menuTree.action",
autoParam:["id", "name=n", "level=lv"],
otherParam:{"otherParam":"zTreeAsyncTest"},
dataFilter: filter
}
}; function filter(treeId, parentNode, childNodes) {
alert("iiii");
if (!childNodes) return null;
for (var i=0, l=childNodes.length; i<l; i++) {
childNodes[i].name = childNodes[i].name.replace(/\.n/g, '.');
}
return childNodes;
}
$(document).ready(function(){
zTreeObj = $.fn.zTree.init($("#treeDemo"),setting);
});
</SCRIPT>
<body>
<div>
<ul id="treeDemo" class="ztree"></ul>
</div>
我刚用ztree,为什么从地址栏打开的时候不能够进入menuTree.action，求解,谢谢哈
2013年08月23日 08点08分
1
var zTreeObj; var setting = {
async: {
enable: true,
url:"menuTree.action",
autoParam:["id", "name=n", "level=lv"],
otherParam:{"otherParam":"zTreeAsyncTest"},
dataFilter: filter
}
}; function filter(treeId, parentNode, childNodes) {
alert("iiii");
if (!childNodes) return null;
for (var i=0, l=childNodes.length; i<l; i++) {
childNodes[i].name = childNodes[i].name.replace(/\.n/g, '.');
}
return childNodes;
}
$(document).ready(function(){
zTreeObj = $.fn.zTree.init($("#treeDemo"),setting);
});
</SCRIPT>
<body>
<div>
<ul id="treeDemo" class="ztree"></ul>
</div>
我刚用ztree,为什么从地址栏打开的时候不能够进入menuTree.action，求解,谢谢哈
