#include<reg51.h>
sbit dula=P2^6;sbit wela=P2^7;sbit beep=P2^3;unsigned char j,k,a1,a0,s=60;unsigned int m;unsigned char code table[]={0x3f,0x06,0x5b,0x4f,0x66,0x6d,0x7d, 0x07,0x7f,0x6f,0x77,0x7c,0x39,0x5e,0x79,0x71};
void delay(unsigned char i){ for(j=i;j>0;j--) for(k=125;k>0;k--);}void display(unsigned char sh_c,unsigned char g_c){ dula=0; P0=table[sh_c]; dula=1; dula=0; wela=0; P0=0xfe; wela=1; wela=0; delay(5); P0=table[g_c]; dula=1; dula=0; P0=0xfd; wela=1; wela=0; delay(5);}
void main(){TMOD=0x01;TR0=1;TH0=(65536-46080)/256;// 由于晶振为11.0592,故所记次数应为46080，计时器每隔50000微秒发起一次中断。TL0=(65536-46080)%256;//46080的来历，为50000*11.0592/12ET0=1;EA=1;while(1){if(m==20){m=0;s--;}a0=s%10;a1=s/10;display(a1,a0);if(s==0){TR0=0;//时间到，定时器关闭beep=0;//蜂鸣器响，报时。}}}
void time0() interrupt 1{TH0=(65536-46080)/256;TL0=(65536-46080)%256;m++;}

不用跪

这问题太炸了，是用数字电路还是MCU，FPGA。。。。呢？

中断单片机完破之