lim(n→∞)(n+c/n-c)^n=25求C

ln25/2？

这个吧也有，哈哈
lim(n→∞) [(n+c)/(n-c)]^n
= lim(n→∞) [(n-c+2c)/(n-c)]^n
= lim(n→∞) [1+2c/(n-c)]^n
= lim(n→∞) [1+2c/(n-c)]^[(n-c)/(2c)*2c/(n-c)*n]
= e^lim(n→∞) 2nc/(n-c)
= e^lim(n→∞) 2c/(1-c/n)
= e^(2c)
e^(2c) = 25
2c = ln25 = 2ln5
c = ln5