迷茫老菜
迷茫老菜
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一个题目哪位高手帮忙完成一下·~ 题目：设计实现抽象的数据类型“有理数”。基本操作包括有理数的加、减、乘、除，以及求有理数的分子。分母。 解答： #include "stdio.h" #include "conio.h" struct rational { int numberator; int denominator; }; void reduce (struct rational *inrat,struct rational *outrat) { int a,b,rem; if (inrat->numberator>inrat->denominator) { a=inrat->numberator; b=inrat->denominator; } else { a=inrat->denominator; b=inrat->numberator; } while (b!=0) { rem=a%b; a=b; b=rem; } outrat->numberator/=a; outrat->denominator/=a; } # define TRUE 1 # define FALSE 0 int equal(struct rational *rat1,struct rational *rat2) { struct rational r1,r2; reduce (rat1,&r1); reduce (rat2,&r2); if(r1.numberator==r2.numberator && r1.denominator==r2.denominator) return (TRUE); return (FALSE); } void multiply(struct rational *r1,struct rational *r2,struct rational *r3) { struct rational rat3; rat3.numberator=r1->numberator*r2->numberator; rat3.denominator=r1->denominator*r2->denominator; reduce(&rat3,r3); } 谁可以给他补上，有错改过！
完成没有完的程序设计（谁来！） 题目：设计实现抽象的数据类型“有理数”。基本操作包括有理数的加、减、乘、除，以及求有理数的分子。分母。解答：#include "stdio.h"#include "conio.h"struct rational{ int numberator; int denominator;}; void reduce (struct rational *inrat,struct rational *outrat) { int a,b,rem; if (inrat->numberator>inrat->denominator) { a=inrat->numberator; b=inrat->denominator; } else { a=inrat->denominator; b=inrat->numberator; } while (b!=0) { rem=a%b; a=b; b=rem; } outrat->numberator/=a; outrat->denominator/=a;}# define TRUE 1# define FALSE 0 int equal(struct rational *rat1,struct rational *rat2) { struct rational r1,r2; reduce (rat1,&r1); reduce (rat2,&r2); if(r1.numberator==r2.numberator && r1.denominator==r2.denominator) return (TRUE); return (FALSE); } void multiply(struct rational *r1,struct rational *r2,struct rational *r3) { struct rational rat3; rat3.numberator=r1->numberator*r2->numberator; rat3.denominator=r1->denominator*r2->denominator; reduce(&rat3,r3); }谁可以给他补上，有错改过！
生活中的困惑～～～ 本人２２岁现在是大学生，可我长这么大还没有谈过恋爱没回看到女孩子都会有点想法，可我就是不敢要不想追求她，心理想的很就是不想行动．大家能不能给点意见！！！我是刚来的很多多关照
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