_Khattiya_ _Khattiya_
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萌新求助,如何求一个未知表达式的多元函数的近似值 有这么一个具体表达式未知的函数f(x,y)=(σ,θ),可以用差分法算出一组函数值{[xn], [yn], [σn], [θn]},但我想求得[xn], [yn]的区间内某个特定的(xi,yi)所对应近似解(σi,θi)(不需要求得拟合方程),用Fit试了一下好像解决不了我这种问题。。。 算例: {(-10 - 9.3`- 8.6`- 7.899999999999999`- 7.1999999999999975`- 6.499999999999999` Null - (43/5) - 7.9`- 7.199999999999998`- 6.4999999999999964`- 5.799999999999999` Null Null - (36/5) - 6.5`- 5.799999999999997`- 5.099999999999997` Null Null Null - (29/5) - 5.1`- 4.4` Null Null Null Null - (22/5) - 3.6999999999999997` Null Null Null Null Null - 3), (7 8.077905474670207` 9.155810949340417` 10.233716424010623` \ 11.311621898680833` 12.389527373351038` Null 7 8.077905474670207` \ 9.155810949340413` 10.233716424010623` 11.311621898680828` Null Null \ 7 8.077905474670207` 9.155810949340413` 10.23371642401062` Null Null \ Null 7 8.077905474670207` 9.155810949340417` Null Null Null Null 7 \ 8.077905474670208` Null Null Null Null Null 7), (15/(1 + Sin[24 \[Degree]]) 26.754129959808232` 42.845283253847164` \ 58.93643654788603` 75.02758984192498` 91.11874313596381` Null 15/(1 + Sin[24 \[Degree]]) 26.754129959808232` 42.84528325384709` \ 58.93643654788604` 75.02758984192485` Null Null 15/(1 + Sin[24 \[Degree]]) 26.754129959808232` 42.8452832538471` \ 58.93643654788595` Null Null Null 15/(1 + Sin[24 \[Degree]]) 26.754129959808232` 42.845283253847164` Null \ Null Null Null 15/(1 + Sin[24 \[Degree]]) 26.754129959808267` Null Null Null Null Null \ 15/(1 + Sin[24 \[Degree]])), (\[Pi]/ 2 1.5707963267948952` 1.5707963267948954` 1.5707963267948961` \ 1.5707963267948966` 1.5707963267948966` Null \[Pi]/ 2 1.5707963267948957` 1.5707963267948963` 1.5707963267948972` \ 1.5707963267948966` Null Null \[Pi]/ 2 1.570796326794896` 1.5707963267948972` 1.570796326794897` Null \ Null Null \[Pi]/ 2 1.5707963267948963` 1.5707963267948963` Null Null Null Null \ \[Pi]/2 1.5707963267948968` Null Null Null Null Null \[Pi]/2)}
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