枫饮寒蝉
枫饮寒蝉
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手头有点紧,买个便宜的,平时跑跑代码,LOL可以玩起来了
纠结中。。。 刚到的y7000p漏光严重,开箱电源线没有电,多送了一个sata转接线,和4根散乱的螺丝钉,第一次开机没点亮。这个要退还是换?
我发表了一篇贴子,大伙来看看吧~
为什么用Nokia recovery tool 刷机,版本还变高了。。 为什么用Nokia recovery tool 刷机,版本还变高了。。还是没法刷成wp8.0.。。
请问920的windows8.1正式版什么时候能收到更新啊? 本人8.1预览版都用3,4个月了,同学的HTC8s 更新成8.1正式版已有月余,可我的一直没收到更新,是不是我的预览版账号有问题?谢谢解答!
急,求神翻译。。。在此谢了 本文针对BP神经网络水质评价模型的不足,引入新型启元式算法海豚群(DPA)算法,将求解BP神经网络最优权值和阈值的过程转化为海豚群捕食寻求最优位置的过程,有效的结合了BP神经网络良好的神经泛化映射能力和DPA算法的全局寻优及局部搜索能力,提出了一种新的地下水质评价方法(DPA-BP),并以磐石市奶牛场8个采样点地下水的测试数据作为测试样本对地下水质进行评价,实验结果表明,DPA-BP算法对地下水质进行评价精确性高、稳定性好,具有较好的鲁棒性和实际工程应用价值。 ---哪位大神能将上述话翻译下在此谢过了!
大恨四六级 7:30冒雨去教室复习六级,现在就困得不行了,想回去睡会。。。这是作死的节奏麽?
920的夜间拍摄真的不敢恭维 ——来自 爱贴吧 Windows Phone 客户端
为毛2级过了,c却全忘了 汗。。。 ——来自 爱贴吧 Windows Phone 客户端
555 2013 Certificate Authority Cup International Mathematical Contest Modeling (mcm.tzmcm.cn) PROBLEM A: Mathematics and Economic Calamity The market crash of 2008 that plunged the world into the economic recession from which it is still reeling had many causes. One of them was mathematics. The financial world is not alone, of course, in depending on mathematical models that aren't always reliable for decision-making guidance. Scientists struggle with models in many fields—including climate science, coastal erosion and nuclear safety—in which the phenomena they describe are very complex, or information is hard to come by, or, as is the case with financial models, both. Those formulas, or models, are only pale reflections of the real world, and sometimes they can be woefully misleading. Despite their ubiquity, these risk models fail to take into account important forces that affect the market. Researchers are building ways to work around these limitations and prevent a repeat market crash. Yet these strategies may limit profits, making it unlikely that banks will adopt them without being forced to do so. If possible, you can redefine risk, then build a dynamic model of some principal factors of the market to monitor the triggers or symptoms to reduce the potential for surprise. Blaming the economic calamity on risk models would be an oversimplification. Other human factors—political and regulatory ones—certainly come into play. How to reduce the impact of human? In addition to the contest's format, prepare a short 1-2 page non-technical letter to the financial investment firms with your final recommendations.
WP8主题被改为这样怎么变回来
指数拟合,错在哪儿?求赐教 t=1790:10:1900; y=[3.9 5.3 7.2 9.6 12.9 17.1 23.2 31.4 38.6 50.2 62.9 76.0]; xData = t; yData = y; % Set up fittype and options. ft = fittype('exp1'); opts = fitoptions(ft); opts.Display='Off'; opts.StartPoint = [4.50256734646774e-019 0.0245343435595401]; % Fit model to data. [fitresult, gof]=fit( xData, yData, ft,opts) % Plot fit with data. figure( 'Name', 'untitled fit 1' ); h = plot( fitresult, xData, yData ); % Label axes grid on
这是肿了么? #include"math.h" #include "stdio.h" void main() { double x[6]={0.0},y[4]={0.0},max=0.0; int i; printf("input 6 deligers:\n"); for(i=0;i<6;i++) scanf("%f",&x[i]); y[0]=5.347*x[0]-0.540*x[1]-0.006*x[2]+0.804*x[3]-0.052*x[4]+27.612*x[5]-482.030; y[1]=5.319*x[0]-0.460*x[1]-0.007*x[2]+1.251*x[3]+0.016*x[4]+27.225*x[5]-505.151; y[2]=5.341*x[0]-0.296*x[1]-0.010*x[2]+0.793*x[3]-0.008*x[4]+26.848*x[5]-480.873; y[3]=5.237*x[0]-0.497*x[1]-0.006*x[2]+0.925*x[3]+0.424*x[4]+28.542*x[5]-497.738; for(i=0;i<=3;i++) { scanf("%f",&y[i]); if(y[i]>max) max=y[i]; printf("y[%d]=%f",i,max); } }
求解释,这运行结果有误吧? #include<stdio.h> #include<math.h> void main() { int i,b=1,c,d=0; for(i=1;i<=2000;i++) b=b*i; printf("%d\n",b); for(c=10;c>0;c=c*10) { if(b%c==0) d++; else break; } printf("%d",d); } 运行结果竟然是0 11 。 为什么?目标是求末尾有几个0.
http://tieba.baidu.com/f?kw=english2 just for share some information
欢迎来吧 创吧伊始,啥也不懂,欢迎光临本吧吖!
请大神看看,哪儿出问题了? include "stdio.h" void main() { char a[2]; printf("input two letters:\n"); scanf("%s",&a[2]); if(a[2]=='MO'||'Mo'||"mO"||"mo") printf("monday\n"); if(a[2]=='TU'||'Tu'||"tU"||"tu") printf("tuesday\n"); if(a[2]=='WE'||'We'||"wE"||"we") printf("wednesday\n"); if(a[2]=='TH'||'Th'||"tH"||"th") printf("thursday\n"); if(a[2]=='FR'||'Fr'||"fR"||"fr") printf("friday\n"); if(a[2]=='SA'||'Sa'||"sA"||"sa") printf("saturday\n"); if(a[2]=='SU'||'Su'||"sU"||"su") printf("sunday\n"); else printf("error"); }
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