这永远就是我 这永远就是我
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呵呵呵 BUG 呵呵，这个是BUG？！
这给卖家有点搞笑 呵呵呵呵呵呵呵 仅为娱乐
魅影计划密码原理： 魅影计划密码原理： 1.Grab the symbols from the map (the hexagrams, not the trigrams) 2.From jjju*s barcode int, people mapped those to unicode values: 0x4dc0, 0x4dc0, 0x4dc1, 0x4dc2, 0x4dc4, 0x4dc7, 0x4dcc, 0x4dd4 3.People also mapped those to the fibonacci sequence (with the value those symbols have in chinese mythology or something): 1 1 2 3 5 8 13 21. This gives us an order. Now it turns out you need to take them from largest to smallest, and I got this idea from the battle log console that references the *max* function. 4.jjju*s formula was pretty explicit showing we were looking for a polynomial, it was missing mostly which value to use as factor and where to start end. 5.Today*s graph picture shows a function that 1) tends to -inf when evaluated at -inf and tends to inf when evaluated at inf. This tells us that the highest x power is odd. 2) It doesn*t cross the origin. And when you look at the graph and evaluates what*s the function value is at the origin, you get a value between 19000 and 20000. This is exactly the range of value of the unicode char. This also tells us that the polynomial has a x0 term. We have 8 unicode values that map from x0 to x7 6.From a chat in game from another dev, we had *X marks the spot* and *the greek X*, which people assumed was related to the console saying CHI = 7.25154120937236. So this gives us the point to evaluate at. The console also mentions the *floor* function which tells us to ignore the decimal part of the result. f = 19924 * x0 + 19916 * x1 + 19911 * x2 + 19908 * x3 + 19906 * x4 + 19905 * x5 + 19904 * x6 + 19904 * x7 f(7.25154120937236) = 24344241893.00018 => passcode = 24344241893 求人来翻译
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